/* SPDX-License-Identifier: GPL-2.0 */
/*
* arch/alpha/lib/ev6-stxcpy.S
* 21264 version contributed by Rick Gorton <[email protected]>
*
* Copy a null-terminated string from SRC to DST.
*
* This is an internal routine used by strcpy, stpcpy, and strcat.
* As such, it uses special linkage conventions to make implementation
* of these public functions more efficient.
*
* On input:
* t9 = return address
* a0 = DST
* a1 = SRC
*
* On output:
* t12 = bitmask (with one bit set) indicating the last byte written
* a0 = unaligned address of the last *word* written
*
* Furthermore, v0, a3-a5, t11, and t12 are untouched.
*
* Much of the information about 21264 scheduling/coding comes from:
* Compiler Writer's Guide for the Alpha 21264
* abbreviated as 'CWG' in other comments here
* ftp.digital.com/pub/Digital/info/semiconductor/literature/dsc-library.html
* Scheduling notation:
* E - either cluster
* U - upper subcluster; U0 - subcluster U0; U1 - subcluster U1
* L - lower subcluster; L0 - subcluster L0; L1 - subcluster L1
* Try not to change the actual algorithm if possible for consistency.
*/
#include <asm/regdef.h>
.set noat
.set noreorder
.text
/* There is a problem with either gdb (as of 4.16) or gas (as of 2.7) that
doesn't like putting the entry point for a procedure somewhere in the
middle of the procedure descriptor. Work around this by putting the
aligned copy in its own procedure descriptor */
.ent stxcpy_aligned
.align 4
stxcpy_aligned:
.frame sp, 0, t9
.prologue 0
/* On entry to this basic block:
t0 == the first destination word for masking back in
t1 == the first source word. */
/* Create the 1st output word and detect 0's in the 1st input word. */
lda t2, -1 # E : build a mask against false zero
mskqh t2, a1, t2 # U : detection in the src word (stall)
mskqh t1, a1, t3 # U :
ornot t1, t2, t2 # E : (stall)
mskql t0, a1, t0 # U : assemble the first output word
cmpbge zero, t2, t8 # E : bits set iff null found
or t0, t3, t1 # E : (stall)
bne t8, $a_eos # U : (stall)
/* On entry to this basic block:
t0 == the first destination word for masking back in
t1 == a source word not containing a null. */
/* Nops here to separate store quads from load quads */
$a_loop:
stq_u t1, 0(a0) # L :
addq a0, 8, a0 # E :
nop
nop
ldq_u t1, 0(a1) # L : Latency=3
addq a1, 8, a1 # E :
cmpbge zero, t1, t8 # E : (3 cycle stall)
beq t8, $a_loop # U : (stall for t8)
/* Take care of the final (partial) word store.
On entry to this basic block we have:
t1 == the source word containing the null
t8 == the cmpbge mask that found it. */
$a_eos:
negq t8, t6 # E : find low bit set
and t8, t6, t12 # E : (stall)
/* For the sake of the cache, don't read a destination word
if we're not going to need it. */
and t12, 0x80, t6 # E : (stall)
bne t6, 1f # U : (stall)
/* We're doing a partial word store and so need to combine
our source and original destination words. */
ldq_u t0, 0(a0) # L : Latency=3
subq t12, 1, t6 # E :
zapnot t1, t6, t1 # U : clear src bytes >= null (stall)
or t12, t6, t8 # E : (stall)
zap t0, t8, t0 # E : clear dst bytes <= null
or t0, t1, t1 # E : (stall)
nop
nop
1: stq_u t1, 0(a0) # L :
ret (t9) # L0 : Latency=3
nop
nop
.end stxcpy_aligned
.align 4
.ent __stxcpy
.globl __stxcpy
__stxcpy:
.frame sp, 0, t9
.prologue 0
/* Are source and destination co-aligned? */
xor a0, a1, t0 # E :
unop # E :
and t0, 7, t0 # E : (stall)
bne t0, $unaligned # U : (stall)
/* We are co-aligned; take care of a partial first word. */
ldq_u t1, 0(a1) # L : load first src word
and a0, 7, t0 # E : take care not to load a word ...
addq a1, 8, a1 # E :
beq t0, stxcpy_aligned # U : ... if we wont need it (stall)
ldq_u t0, 0(a0) # L :
br stxcpy_aligned # L0 : Latency=3
nop
nop
/* The source and destination are not co-aligned. Align the destination
and cope. We have to be very careful about not reading too much and
causing a SEGV. */
.align 4
$u_head:
/* We know just enough now to be able to assemble the first
full source word. We can still find a zero at the end of it
that prevents us from outputting the whole thing.
On entry to this basic block:
t0 == the first dest word, for masking back in, if needed else 0
t1 == the low bits of the first source word
t6 == bytemask that is -1 in dest word bytes */
ldq_u t2, 8(a1) # L :
addq a1, 8, a1 # E :
extql t1, a1, t1 # U : (stall on a1)
extqh t2, a1, t4 # U : (stall on a1)
mskql t0, a0, t0 # U :
or t1, t4, t1 # E :
mskqh t1, a0, t1 # U : (stall on t1)
or t0, t1, t1 # E : (stall on t1)
or t1, t6, t6 # E :
cmpbge zero, t6, t8 # E : (stall)
lda t6, -1 # E : for masking just below
bne t8, $u_final # U : (stall)
mskql t6, a1, t6 # U : mask out the bits we have
or t6, t2, t2 # E : already extracted before (stall)
cmpbge zero, t2, t8 # E : testing eos (stall)
bne t8, $u_late_head_exit # U : (stall)
/* Finally, we've got all the stupid leading edge cases taken care
of and we can set up to enter the main loop. */
stq_u t1, 0(a0) # L : store first output word
addq a0, 8, a0 # E :
extql t2, a1, t0 # U : position ho-bits of lo word
ldq_u t2, 8(a1) # U : read next high-order source word
addq a1, 8, a1 # E :
cmpbge zero, t2, t8 # E : (stall for t2)
nop # E :
bne t8, $u_eos # U : (stall)
/* Unaligned copy main loop. In order to avoid reading too much,
the loop is structured to detect zeros in aligned source words.
This has, unfortunately, effectively pulled half of a loop
iteration out into the head and half into the tail, but it does
prevent nastiness from accumulating in the very thing we want
to run as fast as possible.
On entry to this basic block:
t0 == the shifted high-order bits from the previous source word
t2 == the unshifted current source word
We further know that t2 does not contain a null terminator. */
.align 3
$u_loop:
extqh t2, a1, t1 # U : extract high bits for current word
addq a1, 8, a1 # E : (stall)
extql t2, a1, t3 # U : extract low bits for next time (stall)
addq a0, 8, a0 # E :
or t0, t1, t1 # E : current dst word now complete
ldq_u t2, 0(a1) # L : Latency=3 load high word for next time
stq_u t1, -8(a0) # L : save the current word (stall)
mov t3, t0 # E :
cmpbge zero, t2, t8 # E : test new word for eos
beq t8, $u_loop # U : (stall)
nop
nop
/* We've found a zero somewhere in the source word we just read.
If it resides in the lower half, we have one (probably partial)
word to write out, and if it resides in the upper half, we
have one full and one partial word left to write out.
On entry to this basic block:
t0 == the shifted high-order bits from the previous source word
t2 == the unshifted current source word. */
$u_eos:
extqh t2, a1, t1 # U :
or t0, t1, t1 # E : first (partial) source word complete (stall)
cmpbge zero, t1, t8 # E : is the null in this first bit? (stall)
bne t8, $u_final # U : (stall)
$u_late_head_exit:
stq_u t1, 0(a0) # L : the null was in the high-order bits
addq a0, 8, a0 # E :
extql t2, a1, t1 # U :
cmpbge zero, t1, t8 # E : (stall)
/* Take care of a final (probably partial) result word.
On entry to this basic block:
t1 == assembled source word
t8 == cmpbge mask that found the null. */
$u_final:
negq t8, t6 # E : isolate low bit set
and t6, t8, t12 # E : (stall)
and t12, 0x80, t6 # E : avoid dest word load if we can (stall)
bne t6, 1f # U : (stall)
ldq_u t0, 0(a0) # E :
subq t12, 1, t6 # E :
or t6, t12, t8 # E : (stall)
zapnot t1, t6, t1 # U : kill source bytes >= null (stall)
zap t0, t8, t0 # U : kill dest bytes <= null (2 cycle data stall)
or t0, t1, t1 # E : (stall)
nop
nop
1: stq_u t1, 0(a0) # L :
ret (t9) # L0 : Latency=3
nop
nop
/* Unaligned copy entry point. */
.align 4
$unaligned:
ldq_u t1, 0(a1) # L : load first source word
and a0, 7, t4 # E : find dest misalignment
and a1, 7, t5 # E : find src misalignment
/* Conditionally load the first destination word and a bytemask
with 0xff indicating that the destination byte is sacrosanct. */
mov zero, t0 # E :
mov zero, t6 # E :
beq t4, 1f # U :
ldq_u t0, 0(a0) # L :
lda t6, -1 # E :
mskql t6, a0, t6 # U :
nop
nop
nop
1:
subq a1, t4, a1 # E : sub dest misalignment from src addr
/* If source misalignment is larger than dest misalignment, we need
extra startup checks to avoid SEGV. */
cmplt t4, t5, t12 # E :
beq t12, $u_head # U :
lda t2, -1 # E : mask out leading garbage in source
mskqh t2, t5, t2 # U :
ornot t1, t2, t3 # E : (stall)
cmpbge zero, t3, t8 # E : is there a zero? (stall)
beq t8, $u_head # U : (stall)
/* At this point we've found a zero in the first partial word of
the source. We need to isolate the valid source data and mask
it into the original destination data. (Incidentally, we know
that we'll need at least one byte of that original dest word.) */
ldq_u t0, 0(a0) # L :
negq t8, t6 # E : build bitmask of bytes <= zero
and t6, t8, t12 # E : (stall)
and a1, 7, t5 # E :
subq t12, 1, t6 # E :
or t6, t12, t8 # E : (stall)
srl t12, t5, t12 # U : adjust final null return value
zapnot t2, t8, t2 # U : prepare source word; mirror changes (stall)
and t1, t2, t1 # E : to source validity mask
extql t2, a1, t2 # U :
extql t1, a1, t1 # U : (stall)
andnot t0, t2, t0 # .. e1 : zero place for source to reside (stall)
or t0, t1, t1 # e1 : and put it there
stq_u t1, 0(a0) # .. e0 : (stall)
ret (t9) # e1 :
nop
.end __stxcpy
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